WebMolecular formula: CH 4. Elements: Carbon (C), Hydrogen (H) Molecular weight: 16.043 … WebCH4 (g)+2O2 (g)→CO2 (g)+2H2O (g)ΔH degrees rxn=−802.3kJ Q = 1.17×104 kJ How much hydrochloric acid in grams can be neutralized by 4.00 g of sodium bicarbonate? (Hint: Begin by writing a balanced equation for the reaction between aqueous sodium bicarbonate and aqueous hydrochloric acid.) m= 1.74 g
Chem Exam 5 Flashcards Quizlet
WebMilliliters of methane to grams; 0.1 milliliter of methane = 0.0465 gram: 1 / 5 milliliter of methane = 0.0929 gram: 0.3 milliliter of methane = 0.139 gram: 0.4 milliliter of methane = 0.186 gram: 1 / 2 milliliter of methane = 0.232 gram: 0.6 milliliter of methane = 0.279 gram: 0.7 milliliter of methane = 0.325 gram: 0.8 milliliter of methane ... WebOct 29, 2024 · We are given, 8 g of CH₄ and 16.00 g of O₂ Required to determine the mass of CH₄, O₂, CO₂ and H₂O that remained after the complete reaction. Step 1: Moles of CH₄ and O₂ in the mass given Moles = mass ÷ molar mass Molar mass of CH₄ = 16.04 g/mol Moles of CH₄ = 8.00 g ÷ 16.04 g/mol = 0.498 moles = 0.5 moles Molar mass of O₂ = 16.0 … greek community centre toronto
CH4 (Methane) Molar Mass - ChemicalAid
WebJul 10, 2016 · DeltaH = -"389 kJ" The problem provides you with the thermochemical equation that describes the combustion of methane, "CH"_4 "CH"_ (4(g)) + 2"O"_ (2(g)) -> "CO"_ (2(g)) + 2"H"_ 2"O"_ ((l))" "DeltaH = -"890.3 kJ mol"^(-1) Notice that the thermochemical equation includes the enthalpy change of combustion, which as you … WebA compound has a molar mass of 100 g/mol and the percent composition (by mass) of 65.45% C, 5.45% H, and 29.09% O. Determine the empirical formula and the molecular formula. C3H3O and C6H6O2. The empirical formula of a group of compounds is CHCl. Lindane, a powerful insecticide, is a member of this group. WebMar 25, 2024 · CH4 = 0.25 × 16 = 4 grams O2 = 0 × 32 = 0 gram CO2 = 0.25 × 44 = 11 grams H2O = 0.5 × 18 = 9 grams ** Sorry if there's any mistake. Thank you. Share Improve this answer edited Mar 26, 2024 at 3:26 answered Mar 26, 2024 at 3:18 Sanya 29 6 4 Your final answers were correct. But you have gone awfully long way to prove it. – Mathew … greek community hobart