Dry air was passed successively
WebNov 9, 2024 · Dry air was passed successively through a solution of 5 gm of a solute in 80 gm of water and then through pure ware. The loss in weight of solution was 2.50 gm and that of pure solvent 0.04 gm. A. `70.31` B. `7.143` C. `714.3` D. 80 class-12 solution Share It On FacebookTwitterEmail Please log inor registerto add a comment. WebDry air was passed successively through a solution of 5 g of a solute in 1 8 0 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0. 0 4 g. The molecular weight of the solute is:
Dry air was passed successively
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WebDry air was passed successively through a solution of 5 g a solute in 80 g of water and then through pure water. The loss in mass of solution was 2.5 g and that pure solvent was 0.04 g. What is the molecular mass of the solute? Medium View solution > WebAnswer (1 of 3): There are two ways to look at one scenario and a slightly different case. Warm air can hold much more water vapour than dry air. In terms of "absolute humidity …
WebPerson as author : Pontier, L. In : Methodology of plant eco-physiology: proceedings of the Montpellier Symposium, p. 77-82, illus. Language : French Year of publication : 1965. book part. METHODOLOGY OF PLANT ECO-PHYSIOLOGY Proceedings of the Montpellier Symposium Edited by F. E. ECKARDT MÉTHODOLOGIE DE L'ÉCO- PHYSIOLOGIE … WebDry air was successively passed through a solution of 5g 5 g solute in 80g 80 g water and then through pure water. The loss in weight of solution was 2.5g 2.5 g and that of pure …
WebOct 8, 2024 · Dry air was successively passed through a solution of 5 g solute in 80 g water and then through pure water. The loss in weight of solution was 2.5 g and that of pure water was 0.04 g. What is mol. wt. of … WebDry air was passed successively through a solution of 5 g a solute in 80 g of water and then through pure water. The loss in mass of solution was 2.5 g and that pure solvent …
WebDry air was passed successively through a solution of 5 g of a solute in 180 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0.04 g. The molecular weight of the solute is: Medium View solution >
WebDry air was passed successively through a solution of 5 gm of a solute in 80 gm of water and then through pure water. The loss in weight of solution was 2.50 gm and that of pure … the barbadoes girlWebDry air was passed successively through a solution of \( 5 \mathrm{gm} \) of a solute in \( 180 \mathrm{gm} \) of water and then through pure water. The loss... the grumpy beaver bridgewaterWebMethod: In this method, a stream of dry air is passed successively through (i) a solution (ii) the pure solvent (water) and (iii) a reagent (anhydrous CaCl 2) that can absorb the vapours of the solvent. The complete assembly is shown in the figure, given below: Ostwald - Walker Experiment the bar baccarat hotelWebDry air was passed successively through a P solution of \ ( 5 \mathrm {~g} \) of solute in \ ( 80 \mathrm {~g} \) of water and then Show more Show more 3:42 The molal boiling point … the grumpy economist blogWebDry air was passed successively through a solution of 5 g of a solute in 1 8 0 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0. 0 4 g. The molecular weight of the solute is: the grumpy beaver bridgewater paWebAir was drawn through a solution containing 38 g of solute in 100 g of water, and then through water. The loss of weight of water was 0.0551 g and the total weight of water absorbed in sulphuric acid tube was 2.2117 g. Find the molecular weight of the dissolved substance. Hard View solution > the bar backWebDry air was passed successively through a solution of 5 g of a solute in 180 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0.04 g. The molecular weight of the solute is: Medium View solution > the grumpy bear bukit timah